Question

How many bulbs of 25W can be lighted in circuit with fuse wire of 5A at 250V?

Answer 1

SOLUTION:-

Given:

Potential difference, (V)= 250V

Current, (i)= 5A

So,

Let n bulbs are connected in the circuit, since one bulb have power 25W, therefore n bulbs have 25n watt power.

A/q

P= Vi

=) 25n= Vi

$= > n = \frac{vi}{25} \\ \\ = > n = \frac{250 \times 5}{25} \\ \\ = > n = 10 \times 5 \\ \\ = > n = 50 \: bulbs$

Hope it helps ☺️

Answer 2

here's your answer dear..⏩✨✨❤✌✌❤❤✨