How many bullets can be made out of a cube of lead, whose edge measures 22 cm, each bullet being 2 cm in diameter?
Answer:
Answers
It is based on the concept of volumes.
In order to find the number of bullets, that can be made out of a cube of edge 22 cm, we have to divide the cube's volume by the bullet's volume.
Edge of cube=22 cm
Its volume=a³
=22³
=10648 cm³
So, cube's volume=10648 cm³
Now, diameter of bullet=2 cm
Its radius=D/2=2/2=1 cm
So, its volume=4/3πr³
=4/3×22/7×1³
=4/3×22/7
=88/21 cm³
Now, the number of bullets, that can be made out of a cube of lead of edge 22 cm=cube's volume/bullet's volume
=10648 cm³÷88/21 cm³
=2541
So, the number of bullets that can be made out of a cube of lead of edge 22 cm is 2541
It is based on the concept of volumes.
In order to find the number of bullets, that can be made out of a cube of edge 22 cm, we have to divide the cube's volume by the bullet's volume.
Edge of cube=22 cm
Its volume=a³
=22³
=10648 cm³
So, cube's volume=10648 cm³
Now, diameter of bullet=2 cm
Its radius=D/2=2/2=1 cm
So, its volume=4/3πr³
=4/3×22/7×1³
=4/3×22/7
=88/21 cm³
Now, the number of bullets, that can be made out of a cube of lead of edge 22 cm=cube's volume/bullet's volume
=10648 cm³÷88/21 cm³
=2541
So, the number of bullets that can be made out of a cube of lead of edge 22 cm is 2541
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