Math, asked by reenakhati5, 3 months ago

How many bullets can be made out of a cube of lead, whose edge measures 22 cm, each bullet being 2 cm in diameter?

Answer:

Answers

Answered by prabhas24480
12

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It is based on the concept of volumes.

In order to find the number of bullets, that can be made out of a cube of edge 22 cm, we have to divide the cube's volume by the bullet's volume.

Edge of cube=22 cm

Its volume=a³

=22³

=10648 cm³

So, cube's volume=10648 cm³

Now, diameter of bullet=2 cm

Its radius=D/2=2/2=1 cm

So, its volume=4/3πr³

=4/3×22/7×1³

=4/3×22/7

=88/21 cm³

Now, the number of bullets, that can be made out of a cube of lead of edge 22 cm=cube's volume/bullet's volume

=10648 cm³÷88/21 cm³

=2541

So, the number of bullets that can be made out of a cube of lead of edge 22 cm is 2541

Answered by BrainlyFlash156
6

\huge\underbrace\mathfrak \red{ANSWER }

It is based on the concept of volumes.

In order to find the number of bullets, that can be made out of a cube of edge 22 cm, we have to divide the cube's volume by the bullet's volume.

Edge of cube=22 cm

Its volume=a³

=22³

=10648 cm³

So, cube's volume=10648 cm³

Now, diameter of bullet=2 cm

Its radius=D/2=2/2=1 cm

So, its volume=4/3πr³

=4/3×22/7×1³

=4/3×22/7

=88/21 cm³

Now, the number of bullets, that can be made out of a cube of lead of edge 22 cm=cube's volume/bullet's volume

=10648 cm³÷88/21 cm³

=2541

So, the number of bullets that can be made out of a cube of lead of edge 22 cm is 2541

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