Question

How many bytes are required to store an array declared as int a[5][3] ?​

Answer 1

Answer:

What is an array?

An array is a collection of similar type data . When you declare it (create a memory) for the array you need to mention the size of the array inside “[]” square brackets.

Exact Answer for you :

You wanna declare an array with 55 elements as

double A[55];

This will create in memory as

A[0] , A[2] …. A[54]

So, each double is having 8 bytes (Almost every compiler *May differ)

So that,

55*8 = 440 bytes

Answer 2

Answer:

5×3=15

4 space=55

Explanation:

55 bytes