Question

How many calcium ions are present in 200 g of Calcium carbonate (CaCO3)?​

Answer 1

Answer:

➡First, look at CaCO3 → Ca 2+ + CO3 2-. What does this tell you? Every mol of CaCO3 has 1 mol of Ca2+.

➡What if you were trying to find Na+ of Na2CO3 instead? Na2CO3 -> 2Na+ + CO3 2-. Every mol of Na2CO3 has 2 mol of Na+.

➡This molar relationship is important because it tells us the ratio between the ionic compound and its ions. In order to make use of this relation, we need to convert our current mass to moles. I trust that from reading the other answers you understand how to find molar mass (mol/g): use your current mass (g) / MM (mol/g) = moles of CaCO3 (mol).

➡Since mol CaCO3 : mol Ca2+ is a 1:1 ratio. Mol of CaCO3 = mol Ca2+.

➡From there, you just need to remember the number of ions in a mole, which is Avogadro’s number (6.022 x 10^23 ions/mol), and multiply it by the mol Ca2+ you found. Simple, right?

➡For practice, it might be helpful for you to find the number of Na+ ions in 100 g of Na2CO3? (I got 1.14 x 10^24 ions) Walk through the steps above! Hope that helps.....

please mark as brainliest.........

Answer 2

Calcium Carbonate has ions two of Calcium. It is the chemical compound with the formula CaCO₃

Explanation:

Molar mass of calcium carbonate is 100g/mole

Its molecular mass =40 + 12 + (3 x 16) = 100 g

1 mole of Calcium Carbonate = 100 g of Calcium Carbonate

100 g of Calcium Carbonate has 3 moles of Oxygen atoms = 3 x 6.022 x 10²³ Oxygen atoms.

So, 200 g of Calcium Carbonate has 6 moles of Oxygen atoms = 6 x 6.022 x 10²³ Oxygen atoms.

When CaCO₃ dissociates it gives 2 calcium ions

CaCO₃→  Ca²⁺ + CO₃²⁻