Question

how many calories of heat is required for the external work when one more of a gas is heated bt 1°C at a constant pressure.​

Answer 1

Heat absorbed =ΔQ=nC

p

ΔT=γnC

v

ΔT

Internal energy change=ΔU=nC

v

ΔT

Work done=ΔQ−ΔU=(γ−1)nC

v

ΔT

Required fraction=

γ

γ−1

=1−

γ

1

Answer 2

Answer:

Solution :

Solution :

By definition, energy spent in expansion.

=Cp−Cυ=R=2 calories.