Question

How many carban atoms are present in 0.35 mol of c6H12O6

Answer 1

Answer:

1 mole of C6H12 O6 has = 6 N atoms of C 0.35 mole of C6H 12 O6 has = 6 x 0.35 N atoms of C = 2.1 N atoms = 2.1 x 6.023 x 1023 = 1.26 x 1024 carbon atoms Read more on Sarthaks.com - https://www.sarthaks.com/177080/how-many-carbon-atoms-are-present-in-0-35-mole-of-c6h12o6

Answer 2

Answer:

2.1* 6.023*10^23 carbon atoms

Explanation:

1 mole = 6.023 *10^23 particles

so,0.35 mole = 0.35* 6.023 *10^23 partiles

Now,

in 1 molecule of C6H12O6 contain 6 carbon atom

therefore , 0.35 mole of C6H12O6 contain =6 * 6.023*10^23 * 0.35

=2.1 * 6.023*10^23 carbon atoms