how many carbon atoms are present in 0.1 mol of c6h12o6?
Answers
Answer:
There are 6 carbon atoms/molecule of glucose. Avogadro’s constant (6.02 * 10^23) represents the number of atoms/molecules in a mole (atoms if it is a pure substance). Thus, if you have 0.1mol, you have 0.1 times the number of molecules in a mole, which is 0.1 * Avogadro’s constant. Seeing as you have 6 carbon atoms/molecule, multiply the total number of molecules by 6.
Final Equation:
n * L * N(Carbon)
Where:
n is the number of moles
L is Avogadro’s Constant
N(carbon) is the number of carbon atoms/molecule
n * L * N(carbon)
= 0.1 * (6.02 * 10^23) * 6
= 3.612 * 10^23
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Answer:
6 carbon of atoms are present in c6h12o6
Explanation:
the carbon atom is of one mole of glucose will be 6x6.022x10^23 atoms where we know that for any moles of atom we have this form only.which approximately will be equal