Question

How many carbon atoms are present in 0.35 mol of glucose

Answer 1

Explanation:

C- atoms in one mole of glucose= 6x 6.022x10^23 atoms

so in 0.35 mole = 0.35x 6x6,022x10^23

= 12.64 x10^23

Answer 2

Answer: 8.1 × 6.022 × 10^23

Explanation: 1 molecule of glucose (C612O6) = 6 C-atoms

So 1 mole glucose = 6 mole C-atoms

Then according to question....

0.35 mole of glucose = 6 × 0.35 mole of C-atoms

= 8.1 mole

= 8.1 × 6.022 × 10²³ C-atoms

(1 mole = 6.022 × 10²³ atoms)