Question

how many carbon atoms present in 0.3 mole of C6H12O6? please answer this question in step by step

Answer 1

Explanation:

The carbon atoms in the glucose is 6 so the carbon atoms in one mole of glucose will be 6x 6.022x10^23 atoms where we know that for any moles of atom we have 6.022*10^23 atoms of that molecules.

So, as in the given question 0.35 mole is asked hence number of carbon atoms in 0.35 moles of glucose will be = 0.35x 6x6.022x10^23  

Which will approximately be equal to  12.64 x 10^23 atoms