How many children can be accommodated around a round table if two special boys always sit together. total student is 6.
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fix the two boys
now the remaining for boys can sit in
= 4x3x2x1 number of ways
= 24
and if the two boys also interchange their position the total number of ways become
= 2x24
=48
now the remaining for boys can sit in
= 4x3x2x1 number of ways
= 24
and if the two boys also interchange their position the total number of ways become
= 2x24
=48
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