Question

HOW MANY CHILDREN DOES A FATHER HAVE IF HE GAVE EACH OF THEM ONE-TWELFTH OF A CAKE AND HE ATE THE REMAINING ONE-THIRD?​

Answer 1

Answer:

8 kids

Step-by-step explanation:

split the cake into thirds 3/3 take away dads 1/3= 2/3 two thirds of twelve is 8

Answer 2

Answer:

If the father gave each child 1/12 of a cake and he ate the remaining 1/3, then he has 8 children

Step-by-step explanation:

Let us take x as the number of children

Part of cake the father gave each child = 1/12

Part of cake the children got in total = 1/12 * x = x/12

Part of the cake the father are = 1/3

The total portion of the cake = 1

So,

$\frac{x}{12} + \frac{1}{3} = 1\\\\\frac{3x+12}{12*3} =1\\\\3x +12 = 36\\\\3x = 36-12\\\\3x = 24\\\\x= \frac{24}{3} \\\\x = 8$

So he has 8 children