How many chiral carbons are possible on monochlorination of 2-methylbutane?
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Well obviously you dont directly want the answer but the method to solve it if not so directly go to the pic.
The trick is to locate different hydrogens . Each one will produce a different mono chloro derivative .
Firstly there's a 3° hydrogen then there's a 2° H and then there are 3 methyl groups all having 1°H but the surprise is all the 3 methyl groups are not the same because two of them are bonded to 3° carbon while the other one is bonded to a 2° carbon .
Replace these H atoms by Cl check the stereochemistry of the compound and you have your answer.
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