Question

How many chloride ions are present in a sample of magnesium chloride with a mass of 35.5 grams?

Answer 1

Given:

Mass of Magnesium Chloride in the given sample = 35.5 grams

To find:

No. of chloride ions present in the sample of Magnesium Chloride

Solution:

Molecular Mass of MgCl₂ = 24.31 + (2 * 35.45) = 95.21 g/mol

∴ No. of moles of MgCl₂ = $\frac{mass}{molecular\:mass} = \frac{35.5}{95.21}$ = 0.372 moles

Since the 1 mole of MgCl₂, has 2 moles of Cl

∴ 0.372 moles of MgCl₂ will have = 0.744 moles of Cl

Now, we have,

1 mole = 6.022 × 10²³ ions

∴ No. of chloride ions present in the given sample of MgCl₂ are,

= 0.744 × 6.022 × 10²³

= 4.48 × 10²³ ions

Thus, 4.48 × 10²³ chloride ions are present in a sample of MgCl₂ with a mass of 35.5 grams.

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