Question

How many chlorine atoms are on the products side of the reaction 2Al + 6HCl → 2AlCl3 + 3H2? 2 3 6 9

Answer 1

"Given equation:

$2Al\quad +\quad 6HCl\quad \longrightarrow \quad 2Al{ Cl }_{ 3 }\quad +\quad 3{ H }_{ 2 }$

According to law of conservation of mass, the number of atoms on the reactant side should be equal to the number of atoms on the product side. In the reactant side, the number of chlorine atoms present is 6. In the product side, number of chlorine atom present is $2\quad \times \quad 3\quad =\quad 6$ again. Hence it follows the law. Therefore the number of chlorine atoms in the product side is 6."

Answer 2

The answer is

6

Explanation:

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