How many cm3 of O2 at S.T.P. will be liberated from acidified water by 193 C of electricity
Answers
Answer:
Answer is 2161600 ml
Explanation:
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Answer: The answer is 4351.2 cm3 of O2 liberated from acidified water by 193 C of electricity at S.T.P.
Explanation:
The amount of oxygen (O2) liberated from acidified water by 193 C of electricity at Standard Temperature and Pressure (S.T.P.) can be calculated using Faraday’s law of electrolysis.
Faraday’s law states that the amount of substance liberated by an electric current at a given moment is proportional to the electric current multiplied by the time it has been applied.
Therefore, the amount of O2 liberated from acidified water by 193 C of electricity at S.T.P. can be calculated by multiplying the electric current (193 C) by the time it has been applied to the acidified water and the amount of O2 in one mole of acidified water (1 mole/22.4 L).
The resulting calculation is 193 C x 22.4 L/1 mole, which equals 4351.2 cm3 of O2 liberated from acidified water by 193 C of electricity at S.T.P.
To know more about standard temperature and pressure
https://brainly.in/question/4028492
To know more about Faraday's law
https://brainly.in/question/5008065
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