How many coins 1.75 cm in diameter and 2 mm thick must be melted to form a cuboid of dimensions 11 cm, 10 cm,and 7 cm?
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radius of each coin, r=(1.75/2)cm
(175/200)cm=7/8cm
thickness of each coin, h=2mm
=(2/10)cm=1/5cm
volume of each coin=πr^2h
(22/7*7/8*7/8*1/5)cm^3=(77/160)cm^3
volume of the cuboid =(11*10*7)cm^3=770cm^3
no. of coins=volume of the cuboid /volume of each coin =770*160/77=1600
(175/200)cm=7/8cm
thickness of each coin, h=2mm
=(2/10)cm=1/5cm
volume of each coin=πr^2h
(22/7*7/8*7/8*1/5)cm^3=(77/160)cm^3
volume of the cuboid =(11*10*7)cm^3=770cm^3
no. of coins=volume of the cuboid /volume of each coin =770*160/77=1600
shruti1451:
thanks for your help
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