how many coins 4 cm in diameter and thinkness 1cm must be melted down to from a rectangular solid whose edges are 80cm×15.4cm×10cm.
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Step-by-step explanation:
cuboid= l×b×h
80cm×15.4cm×10cm=
12,320cm^3
volume of cylinder = πr^2h
r= 2cm. h =1cm
= 22/7 × 2^2 × 1
= 22/7 × 4 × 1
= 88/7
=12.57cm^3
volume of cuboid divided by volume of cylinder
12,320cm^3/12.57cm^3
980.1
so nearly 980 coins are needed.
i hope that its correct
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