how many combinations of two digit numbers having 8 can be formed from the following numbers 8956
Answers
Answer:
6 is the answer
89. 85. 86. 68. 58. 98
Answer:
7 combinations are possible.
Step-by-step explanation:
Way to solve the problem:
If repetition of digits is allowed-
_ _
First digit can be chosen in 4 ways. (8, 9 , 5 or 6)
Second digit can also be chosen in 4 ways. (8, 9 , 5 or 6)
Total number of ways in which a two digit combination can be made without any restriction is : 4 x 4 = 16 ways.
Number of ways in which a two digit combination can be made EXCLUDING eight:
First digit can be chosen in 3 ways. ( 9 , 5 or 6)
Second digit can also be chosen in 3 ways. ( 9 , 5 or 6)
Number of ways in which a two digit combination can be made EXCLUDING eight: 3 x 3 = 9 ways.
Therefore,
Number of ways in which a two digit combination can be made having eight is : Total number of ways in which a two digit combination can be made without any restriction - Number of ways in which a two digit combination can be made EXCLUDING eight
= 16-9
=7
(The combinations are 89,88,85,86,68,58,98)
Solved by complementary counting.