how many consecutive natural number starting from 1 should be add to get 300?
Answers
Answered by
8
Answer:
here n= ?
so,
300=n(n+1)/2
600=n²+n
n²+n-600=0
n²+25n-24n-600=0
n(n+25)-24(n+25)=0
(n+25)(n-24)=0
therefore,
n=24
Answered by
3
Step-by-step explanation:
here n= ?
so,
300=n(n+1)/2
600=n²+n
n²+n-600=0
n²+25n-24n-600=0
n(n+25)-24(n+25)=0
(n+25)(n-24)=0
(n+25) =0 or (n-24)=0
n=-25 or n=24
therefore, as negative numbers can't be take
n=24
Similar questions