Math, asked by sonasajan, 6 months ago

how many consecutive natural number starting from 1 should be add to get 300?​

Answers

Answered by Anonymous
8

Answer:

here n= ?

so,

300=n(n+1)/2

600=n²+n

n²+n-600=0

n²+25n-24n-600=0

n(n+25)-24(n+25)=0

(n+25)(n-24)=0

therefore,

n=24

Answered by pritisahare
3

Step-by-step explanation:

here n= ?

so,

300=n(n+1)/2

600=n²+n

n²+n-600=0

n²+25n-24n-600=0

n(n+25)-24(n+25)=0

(n+25)(n-24)=0

(n+25) =0 or (n-24)=0

n=-25 or n=24

therefore, as negative numbers can't be take

n=24

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