How many consecutive natural number starting from 1 should be added to get 300
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consecutive natural numbers will form AP
1,2,3,4,5,6............n
Here, a = 1 d = 1
Sn=300
We are given the sum of an AP which is
Sn=n/2(2a+(n-1)d)
300 = n/2(2+n-1)
600 = n + n²
n² + n - 600 = 0
After solving the above quadratic equation we get
n = 24
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Answered by
1
Answer:
n = 24
Step-by-step explanation:
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