Question

how many consecutive natural numbers from 1 should be added to get 465]​

Answer 1

Answer:

n =30 so and is 30

Step-by-step explanation:

try using progression.

Sn=465

a =1

d=1 because because no more information .

put concept of arithmetic progression .

Sn=n(2a+(n-1)d)/2

solve it for n and u get 30 and -31 so 30 is ur answer

Answer 2

Step-by-step explanation

465 = n(n + 1)/2

$930 = n^{2} + n$

$n^{2} + n - 930$ = 0

$n^{2} + 31n - 30n - 930 = 0$

$n( n + 31) - 30(n + 31) = 0$

$(n +31)(n-30) = 0$

Therefore $n = 30$ or (-31)

But number of terms cannot be negative so (-31) is not possible

So n = 30

So 30 consecutive natural numbers should be added to get 45.

I HOPE IT HELPS