how many consecutive odd number should be add to get 20 cube snd which are they
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Answered by
1
20^3 = 8000
Sn = 8000 = (n/2)[2a+(n-1)d
16000 = n[2+(n-1)]
16000 =n(n+1)
n^2+n-16000,
n1 = [-1+(1+64000)^0.5]/2
= [-1+252.9841892]
= 251.9841892/2
= 125.9920946
So you cannot get consecutive numbers adding up to 20^3.
Answered by
4
Answer:
381,383,385,387,389,391,393,395,397,399,401,403,405,407,409,411,413,415,417,419
Step-by-step explanation:
This is what the answer is...
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