How many consecutive odd numbers from 1 are to be added to get a sum 729
Answers
Answered by
0
Answer:
1+3+5+7+9+11+13+15+17+19+21+23= 23 numbers .
Square is 729.
Answered by
0
Required n=27
Given,
a=1
d=2
n=?
S n=729
Therefore,
S n=n/2[2a+( n - 1)d]
729=n/2[2×1+( n - 1)2]
729=n/2(2+2n-2)
729=n/2(2n)
729=n✓
n =√729
n=27
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