How many coulomb of charge is required for deposition of 2/3 mole of al in electrolysis molten al2o3?
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This question is derived from electrochemistry and it specifically determining the quantitative electrolysis.
What I mean by quantitative electrolysis is that from a given charge we determine the amount of substance deposited.
So going back to your question, you need to appreciate that 1 mole of electron requires 96500 coulomb of charge.
Thus Al³⁺ we have 3 electrons
so we say that 1 e⁻ = 96500 C
3 e⁻ = 3 x 96500
= 289,500 C
therefore 2/3 x 289,500
= 193,000 C.
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