Question

how many coulomb of electricity will be consumed when 100mA current is passed through a solution of AgNO3 for half an hour during electrolysis ?

Answer 1

The amount of current passed $=100 m A=\frac{100}{1000} m A=0.1 A$

Duration for which the current is passed = half an hour

$=\frac{1}{2} h r=\frac{1}{2} \times 60 \times 60 \text { seconds }=1800$

$\mathrm{AgNO}_{3}$ being mono-ionic, its valency does not alter the iconicity of the reacting mixture and hence the coulomb of electricity produced.

Therefore the coulomb of electricity produced when 100mA current is passed through $\mathrm{AgNO}_{3}$ solution for half an hour  

$\begin{array}{l}{=\text { current passed } \times \text { time of passage of current }} \\ {=0.1 \times 1800=180 \text { coulomb. }}\end{array}$