Question

How many coulombs are required to deposists 50gm of alumunium when the electrode reaction is Al3+3e give rise to Al​

Answer 1

Answer:

Al3++3e-→Al. (Given , atomic mass of Al =27 g mol-1,F=96500Cmol-1) To deposit, 5.4 g of Al (s), the amount of charge required=(3×96500C)(27g)×(5.4g)=57900C=5.79×104C.

Explanation:

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