Question

How many coulombs are required to produce 20 g of calcium from molten cacl2?

Answer 1

1 Faraday is used to produce 20 grams of calcium from cacl2.

Explanation:

since cacl2=ca2+ + 2 cl-

ca2+ +2e- = ca

so 2 moles of electrons are required to produce 1 mole of calcium Or 40 grams of calcium

so 1 mole of electrons are required to produce 20 grams of calcium.

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Answer 2

Answer:

The coulombs, which are required to produce $20 g$ of calcium from molten $CaCl_{2}$ is $96500 coulombs$.

Explanation:

Given,

The mass of calcium from molten $CaCl_{2}$ = $20g$

The charge required to produce $20g$ of calcium from molten $CaCl_{2}$ =?

As we know,

The molar mass of calcium = $40g/mol$

• The dissociation of $CaCl_{2}$ occurs in the way given below:
• $CaCl_{2} (aq) \rightarrow Ca(s) + Cl_{2}(g)$

The half cell reaction is:

• $Ca^{2+}(aq) + 2e^{-} \rightarrow Ca (s)$
• $1mole$     $2 Faraday$   $1 mole$

From this, we can say that 1 mole of $Ca$ has $2 F$ of charge.

Now,

• The number of moles of calcium = $\frac{Given mass}{Molas mass}$ = $\frac{20}{40}$ = $0.5 mol$

Thus,

• $1 mole$ = $2F$
• $0.5 moles$ = $0.5\times 2F$ = $1F$

And, 1 F = $96500 coulombs$.

Hence, the charge required to produce $20g$ of calcium from molten $CaCl_{2}$ = $96500 coulombs$.