How many coulombs are required to produce 27gm of silver from AgNo3
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Answer:
Explanation:
Al2O3+6e−→2Al+3O2− 6mol 2mol
The charge Q on n mol of electrons is given by Q=nF
Thus,quantity of electricity required to deposit 2 moles of aluminium, Q=6mol×96500 C mol−1=579000C=5.79×105C
Molar mass of Al =27 g mol−1
Mass of 2 mol of Al=2mol×27gmol−1=54g
∴54gofAl is produced by electric charge=5.79×105C
50gofAl is produced by electric charge=(5.79×105C)(564g)(50g)=5.361×105C
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