How many coulombs are required to produce 50 gm of Al when electrode
reaction is
Al"+ 3e Al (atomic mass of Al-27).
Answers
Answered by
0
Answer:
can't understand your question
Answered by
1
Answer:
Al
3+
+3e
−
→Al
3mole
−
→27g of Al
5.4g→
27
3
×5.4=0.6mol of e
−
no. of F=
96500
Q
=0.6
Q=0.6×96500=57900C
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