How many cross aldol products (without counting
stereoisomers) are produced in the following reaction?
O
||
CH - CH = O + CH - C- CH □(→┴NaOH )
(a) 5 (b) 2
(c) 3 (d) 1
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Answer:
(d)1 ✔✔
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The number of cross aldol products formed (without counting stereoisomers) are 1
- Aldol condensation: The process of reacting aldehydes or ketones in presence of dil. NaOH to β hydroxy aldehyde or β hydroxy ketone known as Aldol.
- Aldol condensation produces 4 products.
- But if one of reacting species doesn;t have α Hydrogen atom , then only 2 products are formed, as in this case.
- It behaves just as a anion acceptor.
- Also , it is said to not count on stereoisomers.
- Therefore we have only 1 product left.
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