Question

how many cubes of 16 cm can be fitted into a box with measures 3.2 m*80m*64m


plz tell fast​

Answer 1

❏ Question:-

@how many cubes of 16 cm can be fitted into a box with measures 3.2 m*80m*64m???

❏ Solution:-

✦Given:-

• side of cube= 16 cm

• Dimension of the cuboidal box

=( 3.2m × 80m × 64m )

∴ length (l) of the box=3.2 m=(3.2×100) cm

∴ breadth (b) of the box =80 m=(80×100) cm

∴ height (h) of the box=64 m= (64×100) cm

✦To Find:-

• No. of cubes which can be fitted in

that cuboidal box.

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✰ Let's Head the problem Now:-

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➝Volume of the box

=[(3.2×80×64)×1000000] cm³

and,

➝ Volume of the cube= [16³] cm³

$\therefore$No. of cubes that can be fitted into this cuboidal box is ,

$\sf\longrightarrow \bf \frac{\text{Volume of the Box}}{\text{Volume of each cube}}$

$\sf\longrightarrow \bf \frac{3.2\times80\times64\times10,00,000}{16{}^{3}}$

$\sf\longrightarrow \bf \frac{\cancel{3.2}\times\cancel{80}\times\cancel{64}\times10,00,000}{\cancel{16}\times\cancel{16}\times\cancel{16}}$

$\sf\longrightarrow \bf 0.2\times5\times4\times 10,00,000$

$\sf\longrightarrow \boxed{\large{\red{40,00,000 \:\:pcs.}}}$

$\therefore$ No. of cubes that can be fitted is =40,00,000 pcs.

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✰Some Used ForMuLaS:-

✦CUBOID✦

For a cuboid of length l , breadth b and height h .

$\sf\longrightarrow\boxed{ Diagonal=\sqrt{l^{2}+b^{2}+h^{2}}}$

$\sf\longrightarrow\boxed{T.S.A.=2\times(lb+bh+hl)}$

$\sf\longrightarrow\boxed{ Volume=l\times b\times h}$

Where, •T.S.A.=Total Surface area.

✦CUBE✦

For a Cube of Side a ,

$\sf\longrightarrow\boxed{ Diagonal=\sqrt{3}\times side}$

$\sf\longrightarrow\boxed{T.S.A.=6\times side{}^{2}}$

$\sf\longrightarrow\boxed{ Volume=Side^{3}}$

Where, •T.S.A.=Total Surface area.

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$\underline{ \huge\mathfrak{hope \: this \: helps \: you}}$

Answer 2

Answer:

4000000 Cubes can be fitted in the Cuboidal Box

Step-by-step explanation:

We Have :-

Cuboidal Box with measure:-

Length = 3.2m = 320cm

Breadth = 80m = 8000 cm

Height = 64m = 6400 cm

Cube With Side = 16cm

To Find :-

How many Cubes can be fitted into the Cuboidal Box

Formula Used :-

Volume of Cuboid = Length * Breadth * Height

Volume of Cube = Side³

Solution :-

Let the number of cubes be N

$Volume\ of\ Cuboidal\ Box = 320 * 8000 * 6400\\\\= 16384000000 cm^{3} \\\\Volume\ of\ Cube = 16^{3} \\\\= 4096cm^{3} \\\\Volume\ of\ Cuboidal\ Box\ = N* Volume\ of\ Cube\\\\16384000000 = N * 4096\\\\N = 4000000$