Question

How many cubes of side 2 cm each can be adjusted within a larger cube of volume 512 cm3?

Answer 1

Answer:

Volume of 1 cube

$= 2 \times 2 \times 2 \\ = 8 {cm}^{3}$

No of cubes that can fit in 512 cm3

$n = \frac{512}{8}$

$n = 64 \: cubes$

Answer 2

Answer:

Solution: If a cube has a volume of 512 cm^3, then each edge = 512^(1/3) = 6 cm. Answer.

Further information:

Total surface area = 6(6*6) = 512 cm^2.

The internal diagonal = 6√3 = 10.39 cm.

The diagonal on the faces = 6√2 = 8.49 cm.