How many cubic centimeter of iron is required to construct an open box whose external dimensions are 36cm,25cm, and 16.5 cm provided the thickness of the iron is 1.5cm. If one cubic cm of iron weighs 7.5g find the weight of the box.
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External dimensions of open box = 36 × 25 × 16.5 cm
External volume of box = 14850 cm³
Internal dimensions of open box = (36 - 2 × 3.5) cm × (25 - 2 × 3.5) cm × (16.5 - 3.5) cm
= 29 × 18 × 13 cm
Internal volume of the box = 6786 cm³
Volume of wood = External Volume of the box - Internal Volume of the box
= 14850 - 6786 = 8064 cm³
Weight of 1 cubic cm of iron = 7.5 g
Weight of 8064 cubic cm of iron = 8064 × 7.5
= 60480 g = 60.48 kg
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External volume of box = 14850 cm³
Internal dimensions of open box = (36 - 2 × 3.5) cm × (25 - 2 × 3.5) cm × (16.5 - 3.5) cm
= 29 × 18 × 13 cm
Internal volume of the box = 6786 cm³
Volume of wood = External Volume of the box - Internal Volume of the box
= 14850 - 6786 = 8064 cm³
Weight of 1 cubic cm of iron = 7.5 g
Weight of 8064 cubic cm of iron = 8064 × 7.5
= 60480 g = 60.48 kg
HOPE IT HELPS YOU!
PLS MARK AS BRAINLIEST
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