Question

How many cubic centimeters of water can a conical vessel of base diameter 42 cm and slant height 29 cm hold?​

Answer 1

Step-by-step explanation:

Diameter = 42 cm

Radius = 42/ 2 = 21 cm

Slant height = 29 cm

29 ^2 = 21^2 + H^2

height = 20 cm

volume of cone = 1/3 pir^2h

= 1/3× 22/7 × 21 × 21 × 20

21 × 21 × 20

8820 cm cube

Answer 2

Answer:

amount of water the given conical vessel can hold = 9240cm³

Step-by-step explanation:

given, base diameter = 42cm

⇒ radius of conical vessel (r) = 21cm

slant height (l) = 29 cm

height of the conical vessel (h) = $\sqrt{29^{2}-21^{2} }$

⇒h = √(841-441)

⇒h =√400

⇒h= 20cm

volume of cone = $\frac{1}{3} *\pi *r^{2}*h$

⇒volume = $\frac{1}{3} *\frac{22}{7} *21^{2} *20$

⇒volume = 9240cm³

hence, amount of water the given conical vessel can hold = 9240cm³