Question

HOW MANY CUBIC CENTIMETRES OF IRON ARE THERE IN AN OPEN BOX WHOSE EXTERNAL DIMENSION ARE 36CM,25CM,16.5CM.THE IRON BEING 1.5CM THICK THROUGHOUT?IF 1CM^3 of Iron weighs 15g,find the weight of the empty box in kilogram​

Answer 1

Hello dude
here is ur answer

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External volume (without counting hollow part) = 36 × 25 × 16.5 = 14850 cm

Internal dimensions of box:
=> 36-2(1.5) = 33cm
=> 25-2(1.5) = 22cm
=> 16.5-2(1.5) = 13.5cm
Volume of hollow part in box = 33 × 22 × 13.5 = 9801 cm

Box is open, therefore top part must be removed.
Volume of top part = 36 × 25 × 1.5 = 1350 cm

Therefore, volume of box = 14850-9801-1350 = 3699 cm

Weight of empty box = 3699 × 15 = 55485g = 55.485 kg

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