Question

How many cubic centimetres of iron is required to construct an open box whose external dimensions are
36 cm, 25 cm and 16.5 cm provided the thickness of the iron is 1.5 cm. If one cubic cm of iron weighs 7.5
g, find the weight of the box.​

Answer 1

Answer:

Volume = external - internal

= L*B*H - l*b*h

=36*25*16.5 - 33*22*15(36-3,25-3,16.5-1.5)

=14850 - 10890

=3960 cm^3

Weight = 3960 * 7.5 = 29700g

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Answer 2

Answer:

55.48kg

Step-by-step explanation:

External volume (without counting hollow part) = 36*25*16.5 = 14850 cc

Internal dimensions of box:

=> 36-2(1.5) = 33cm

=> 25-2(1.5) = 22cm

=> 16.5-2(1.5) = 13.5cm

Volume of hollow part in box = 33*22*13.5 = 9801 cc

Box is open, therefore top part must be removed.

Volume of top part = 36*25*1.5 = 1350 cc

Therefore, volume of box = 14850-9801-1350 = 3699 cc

Weight of box = 3699*15 = 55485g = 55.48 kg