How many cubic centimetres of iron is required to construct an open box whose external dimensions are
36 cm, 25 cm and 16.5 cm provided the thickness of the iron is 1.5 cm. If one cubic cm of iron weighs 7.5
g, find the weight of the box.
Answers
Answered by
11
Answer:
Volume = external - internal
= L*B*H - l*b*h
=36*25*16.5 - 33*22*15(36-3,25-3,16.5-1.5)
=14850 - 10890
=3960 cm^3
Weight = 3960 * 7.5 = 29700g
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Answered by
4
Answer:
55.48kg
Step-by-step explanation:
External volume (without counting hollow part) = 36*25*16.5 = 14850 cc
Internal dimensions of box:
=> 36-2(1.5) = 33cm
=> 25-2(1.5) = 22cm
=> 16.5-2(1.5) = 13.5cm
Volume of hollow part in box = 33*22*13.5 = 9801 cc
Box is open, therefore top part must be removed.
Volume of top part = 36*25*1.5 = 1350 cc
Therefore, volume of box = 14850-9801-1350 = 3699 cc
Weight of box = 3699*15 = 55485g = 55.48 kg
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