Question

How many cyclic subgroups of order 10 in z100 x z25?

Answer 1

hey I am jubber Jan answered you. plz mark me as brainest. your answer is ż 2500

Answer 2

$=z^{125}$

Step-by-step explanation:

We have,

$z^{100}\times z^{25}$

To find, how many cyclic subgroups of order 10 in $z^{100}\times z^{25}=?$

∴ $z^{100}\times z^{25}$

$=z^{100+25}$

Using the identity,

$a^{m}\times a^{n}=a^{m+n}$

$=z^{125}$

Hence, total number of cyclic subgroups of order 10 = 125