Math, asked by bspvigvaw, 24 days ago

how many defective pieces will be in a lot of 20000 pieces of toy, if the process is adjudged as 3 sigma level.

Answers

Answered by ajitgodakhindi
0

Answer:

Given  - 20000 toys per lot

Process is 3 sigma

3 sigma means 3 defects per 1000

For 20000 lot = 20000 * 3/1000 = 60 defects

Answered by niteshrajputs995
0

Answer:

3-sigma level of quality control, approximately 27 pieces of the lot of 20000 pieces of toy would be defective.

Question : How many defective pieces will be in a lot of 20000 pieces of toy, if the process is adjudged as 3 sigma level.

Step-by-step explanation:

From the above question,

They have given :

The 3-sigma degree of great manage is a measure of pleasant assurance that states that any system ought to produce no extra than three widespread deviations (or 99.73%) of defects.

This potential that the system ought to yield no greater than 0.27% of faulty results, making it a very excessive fashionable of fine control.

It is frequently used in manufacturing and manufacturing processes, as it ensures that the majority of the merchandise produced will be of excessive first-class and that the wide variety of faulty merchandise is stored to a minimum.

The 3-sigma stage of nice manipulate is a general of fantastic assurance that states that any manner need to produce no greater than three popular deviations (or 99.73%) of defects.

This capability that the manner have to yield no extra than 0.27% of faulty results, making it a very excessive widespread of first-class control.

Assuming a 3-sigma degree of great control, about 27 portions of the lot of 20000 portions of toy would be defective.

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