Math, asked by ajitd7901, 1 month ago

How many degrees are there in 2/5 straight angle

Answers

Answered by seemasharmadhn8556
3

Answer:

Trigonometry is one way. 180 degrees - 150.5 degrees is 29.5 degrees. So angles measuring 150.5 + 29.5 degrees are supplementary.

Trigonometry is one way. 180 degrees - 150.5 degrees is 29.5 degrees. So angles measuring 150.5 + 29.5 degrees are supplementary.Draw a horizontal line. Label 3 points on the line, A, B, and C starting far left end of the line, middle, and far right. Label a point D above A so that AD is a shorter distance than AB. Draw a line from B to D and another from D down to A. So you have a right triangle ABD. Label angle ABD as being 29.5 degrees. Then the angle DBC (from D to B to C) is 150.5 degrees.

Trigonometry is one way. 180 degrees - 150.5 degrees is 29.5 degrees. So angles measuring 150.5 + 29.5 degrees are supplementary.Draw a horizontal line. Label 3 points on the line, A, B, and C starting far left end of the line, middle, and far right. Label a point D above A so that AD is a shorter distance than AB. Draw a line from B to D and another from D down to A. So you have a right triangle ABD. Label angle ABD as being 29.5 degrees. Then the angle DBC (from D to B to C) is 150.5 degrees.Of course your first sketch would not be accurate since you guess at how far above A to put D. But let’s try again. Carefully put B 100 cm from A. We will calculate how high above A you need to put D. The 100 cm AB will be the adjacent side of the 29.5 degree angle. So, place point D a distance of

Trigonometry is one way. 180 degrees - 150.5 degrees is 29.5 degrees. So angles measuring 150.5 + 29.5 degrees are supplementary.Draw a horizontal line. Label 3 points on the line, A, B, and C starting far left end of the line, middle, and far right. Label a point D above A so that AD is a shorter distance than AB. Draw a line from B to D and another from D down to A. So you have a right triangle ABD. Label angle ABD as being 29.5 degrees. Then the angle DBC (from D to B to C) is 150.5 degrees.Of course your first sketch would not be accurate since you guess at how far above A to put D. But let’s try again. Carefully put B 100 cm from A. We will calculate how high above A you need to put D. The 100 cm AB will be the adjacent side of the 29.5 degree angle. So, place point D a distance oftan29.5 = opposite (AD) / adjacent (AB), therefore

Trigonometry is one way. 180 degrees - 150.5 degrees is 29.5 degrees. So angles measuring 150.5 + 29.5 degrees are supplementary.Draw a horizontal line. Label 3 points on the line, A, B, and C starting far left end of the line, middle, and far right. Label a point D above A so that AD is a shorter distance than AB. Draw a line from B to D and another from D down to A. So you have a right triangle ABD. Label angle ABD as being 29.5 degrees. Then the angle DBC (from D to B to C) is 150.5 degrees.Of course your first sketch would not be accurate since you guess at how far above A to put D. But let’s try again. Carefully put B 100 cm from A. We will calculate how high above A you need to put D. The 100 cm AB will be the adjacent side of the 29.5 degree angle. So, place point D a distance oftan29.5 = opposite (AD) / adjacent (AB), thereforeAD = 100 cm*tan29.5 = 56.58 cm

Trigonometry is one way. 180 degrees - 150.5 degrees is 29.5 degrees. So angles measuring 150.5 + 29.5 degrees are supplementary.Draw a horizontal line. Label 3 points on the line, A, B, and C starting far left end of the line, middle, and far right. Label a point D above A so that AD is a shorter distance than AB. Draw a line from B to D and another from D down to A. So you have a right triangle ABD. Label angle ABD as being 29.5 degrees. Then the angle DBC (from D to B to C) is 150.5 degrees.Of course your first sketch would not be accurate since you guess at how far above A to put D. But let’s try again. Carefully put B 100 cm from A. We will calculate how high above A you need to put D. The 100 cm AB will be the adjacent side of the 29.5 degree angle. So, place point D a distance oftan29.5 = opposite (AD) / adjacent (AB), thereforeAD = 100 cm*tan29.5 = 56.58 cmSo carefully place point D exactly vertically above A and 56.58 cm from A. Draw in lines AD and BD. Your angle ABD measures 29.5 degrees. And the angle that is supplementary to the 29.5 degree angle is 150.5 degrees. And you have constructed it.

Answered by atharvakumbhar3099
2

Answer:

120° is your answer

Step-by-step explanation:

hope it will be helpful for you if yes then please mark as brainliest

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