Question

How many degrees of freedom are associated with 2 grams of helium at NTP? Calculate the amount of heat energy required to raise the temp. of this amount from 27°C to 127°C. Given Boltzmann constant, kB = 1.38 × 10^-16 erg molecule^-1 K^-1 and Avogadro's number = 6.02 × 10^23.​​

Answer 1

Answer:

50 is the answer ok

this is a good time

Answer 2

Step-by-step explanation:

Here, mass of He=2 gram and its atomic wt. =4

As, No atoms in 4gram-6-02×1023, No of atoms in 2gram=6.02×10²3×2=3.01×1023 4 As, He is monotomic, each molecule has three degree of freedom.

.. Total no. of degree of freedom = 3×3.01× 10²³-9.03×1023

As energy associated with one degree of free

dom per molecule = KÅT

atT₁=(27°C)=300K, heat content of gas U₁-9-03×1023xKBT1-9.03×1023 x 1 x1.38×10-23×300J=1869.2J Similarly at T2=127=(127+273) K=400

K

U2=9.03×10²³××1.38×10-2³×400J=

2492.3J

Hence energy required to raise the temp. of gas from 300 Kto400K is U-U2-U₁=2492.3-1869.2-623.1joule.