how many diagonals are there in a polygon with n sides
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D = s(s-3)/2
D = Diagonals
s = side
D = Diagonals
s = side
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Answer is 3 diagonals.
Number of diagonals = n ( n - 3 ) /2 [ Where n is the number of polygon sides ]
Number of diagonals = n ( n - 3 ) /2 [ Where n is the number of polygon sides ]
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