Question

How many diagonals can you draw in a heptagon? Explain the difference between diagonal and adjacent side by using a suitable polygon.

WHOEVER ANSWER THIS I WILL MARK THEM AS A BRAINLIEST

Answer 1

Answer:

The number of diagonals can be found by: n•(n-3)/2.

So in this case :7•(7 - 3)/2 = 7•4/2 = 14 diagonals

Step-by-step explanation:

The formula works because each vertex, n, has (n - 3) diagonals because you can’t draw a diagonal from a vertex to itself, or to the vertex immediately to the left or right of the given vertex, as these are not diagonals but exterior sides instead. The final step is to divide by 2 because otherwise a diagonal connecting vertex 1 with vertex 3 will be counted twice, once in the vertex 1 count and once in the vertex 3 count.

Answer 2

Step-by-step explanation:

To Find:

• Number of diagonals you can draw in a heptagon

Solution:

Formula to find the number of diagonal=

$\tt \leadsto \: \frac{n(n - 3)}{n}$

So,

$\tt \leadsto\: \frac{n(n - 3)}{n} \\ \tt \leadsto \frac{7(7 - 3)}{2} \\ \tt \leadsto \frac{7 \times \cancel4}{ \cancel2} \\ \tt \leadsto7 \times 2 = 14 \: diagonals$

We can draw 14 diagonals in a heptagon