Math, asked by vplsngh54, 11 months ago

how many different 6 digit numbers can be formed using digits in the number 659942? how many of them are divisible by 4?​

Answers

Answered by amitnrw
12

360 different 6 digit numbers can be formed using digits in the number 659942 ,  96 of them are divisible by 4

Step-by-step explanation:

6 digit numbers can be formed using digits in the number 659942

6 digit are there , but 9 is repeated twice

= 6!/2!

= 360  Numbers

Number would be divisible by 4 if last two digits are divisible by 4

Hence number ending with

24  ,  52 , 56  , 64  ,  92 , 96 are divisible by 4

Taking each case

Last two digit  24  then  possible numbers   4!/2!  = 12

Last two digit  52  then  possible numbers   4!/2!  = 12

Last two digit  56  then  possible numbers   4!/2!  = 12

Last two digit  64 then  possible numbers   4!/2!  = 12

Last two digit  92  then  possible numbers   4! = 24

Last two digit  96  then  possible numbers   4! = 24

Hence number divisible by 4  = 12 + 12 + 12 + 12 + 24 + 24

= 96

360 different 6 digit numbers can be formed using digits in the number 659942 ,  96 of them are divisible by 4

Learn more:

How many numbers formed with the digits0, 1, 2, 5, 7, 8 will fall ...

https://brainly.in/question/12803929

How many three-digit even numbers which are divisible by 11 also ...

https://brainly.in/question/12862192

How many three digit numbers which are neither divisible by 4 nor 5 is

https://brainly.in/question/13181275

Similar questions