How many different arrangement are possible from the letters of the word calculation
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Anonymous:
Reconsider your answer ....... or correct mine
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No. of letters = C, A, L, U, T, I, O, N
.'. No. of Arrangements =/ (2! * 2! * 2!)= 11! / (2! * 2! * 2!) = 4989600
.'. No. of Arrangements =/ (2! * 2! * 2!)= 11! / (2! * 2! * 2!) = 4989600
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