Math, asked by muzammilp71, 5 months ago

How many different arrangement of the letters of the word BOUGHT can be formed if the vowels must be kept next to each other​

Answers

Answered by arunachaleswaraautoc
0

Answer:

ways which is 24. Therefore the total number of permutations that we can have is 24X10 = 240.

Answered by Syamkumarr
0

Answer:

The answer is 240.

Step-by-step explanation:

Given word BOUGHT

Vowel letters in given word = O, U

consonant letters in given words = B, G, H, T

Let's take OU as one unit

therefore number words can be formed with letters  OU, B, G, H, T  

       = 5!           [  ∵ number of letters will be 5 ]

here OU can arranged among them

then number of arrangement among O,U = 2!

Number of arrangements in word BOUGHT if the vowels are kept next to each other = 5! × 2! =  5×4×3×2×1×2×1 = 240

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