Question

How many different inyegers exist between 10^6 and 10^7, the sum of whose digits is 2​

Answer 1

Step-by-step explanation:

6 integers starting with 1 with sum of digits equal to 2 and one integer starting with 2. Hence, a total of (6 + 1) = 7 integers.

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Answer 2

How many different positive integers exist between 10^6 and 10^7, the sum of whose digits is equal to 2? We can have 6 integers starting with 1 with sum of digits equal to 2 and one integer starting with 2. Hence, a total of (6 + 1) = 7 integers. The correct answer is b.