How many different kinds of rectangles can you make with the perimeter of 24cm? Find the area of each rectangle. Write your conclusion.
Answers
Answered by
6
(You haven't mentioned, so I am assuming, we need integer solutions for length and breadth)
So, Perimeter of rectangle = 24 cm
Perimeter = 2(L + B) = 24 where L > W
2(L + B) = 24
L + B = 12
The set of breadths B and lengths L that satisfy this equation are (B, L)
(1,11)
(2,10)
(3,9)
(4,8)
(5,7)
(6,6)
Areas of such sets of (B, L) are given by B x L,
(1,11) = 11 cm²
(2,10) = 20 cm²
(3,9) = 27 cm²
(4,8) = 32 cm²
(5,7) = 35 cm²
(6,6) = 36 cm²
So, Perimeter of rectangle = 24 cm
Perimeter = 2(L + B) = 24 where L > W
2(L + B) = 24
L + B = 12
The set of breadths B and lengths L that satisfy this equation are (B, L)
(1,11)
(2,10)
(3,9)
(4,8)
(5,7)
(6,6)
Areas of such sets of (B, L) are given by B x L,
(1,11) = 11 cm²
(2,10) = 20 cm²
(3,9) = 27 cm²
(4,8) = 32 cm²
(5,7) = 35 cm²
(6,6) = 36 cm²
Varooni:
let me see if that is ok cause we need 3 rectangles
Answered by
3
Answer:
I hope it will help you a lot
Attachments:
Similar questions
Science,
8 months ago
Chemistry,
8 months ago
Physics,
1 year ago
French,
1 year ago
Social Sciences,
1 year ago