How many different (non-congruent) triangles can you draw with two sides 8 and 6 centimetres and area 12 square centimetres? What if the area is to be 24 square centimetres?
Answers
Answer:
There will be two non-congruent triangles with two sides 6 cm and 8 cm, whose area will be 12 cm^2. This is because, if base of the triangle is 6 cm then its height must be 4 cm to get the area =12 cm^2.
Step-by-step explanation:
Mark me as brainlist.
Answer:
There will be two non-congruent triangles with two sides 6 cm and 8 cm, whose area will be 12 cm^2. This is because, if base of the triangle is 6 cm then its height must be 4 cm to get the area =12 cm^2.
(Since, area of a triangle =1/2 x base x height). So, while doing the construction we will have to draw a line parallel to the base, at a distance of 4 cm from it, on which the third vertex of the triangle will lie. Then with one of the vertex of the base as centre if we draw an arc with radius 8 cm. It will intersect the line parallel to the base at 2 points. By joining those 2 points with another vertex of the base we get those two possible triangles.
Now, if area of the triangle =24 cm^2 and
Base =6 cm (say)
Then, height of the triangle =8 cm
(Since, area of a triangle =1/2 x base x height)
Therefore, only one such triangle