How many different numbers between 100 and 1000 can be formed using the digits 0
1, 2, 3, 4, 5, 6 assuming that
these will be divisible by 5 ?
give answer this question quickly
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1
Answer:
83
Step-by-step explanation:
Excluding 100 and 1000.
- must be 3 digit number.
- divisible by 5 i.e last digit can be either 5 or 0
- first digit can not be 0
So,
- first digit has 6 option
- second one has 7
- third one has 2
We have 6 * 7 * 2 possibility in total, this includes 100
Total possible number = 84 -1 = 83
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