How many different numbers of seven digits can be formed using 1,2,0,1,2,2,5 that are divisible by 10?
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Step-by-step explanation:
no of ways=7!/3! 2!-6!/3! 2!
=7*6*5*4*3*2/3*2*2-6*3*4*3*2/3*2*2
=420-60=360
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